RomanKatz
Industrial
- Aug 29, 2012
- 52
Hello friends,
I am trying to calculate the required Q for a double jacket 10m3 vessel heated by a small boiler. If I do the Q=mcdt equation it turns out 500 kg,60 degC difference about 30+Kw.
How ever If I calculate the resistance of heating the water,convection to and throught the copper jacket, then the vessel and into material it turns about 10Kw wich is much closer to the real value because there was a heating boiler of about 7Kw that operated for 2 hr to heat the material that was latter taken appart(I dont know the final temp, only that was good enought).
So what am I missing?
Thanks
Best Regards
Roman Katz
I am trying to calculate the required Q for a double jacket 10m3 vessel heated by a small boiler. If I do the Q=mcdt equation it turns out 500 kg,60 degC difference about 30+Kw.
How ever If I calculate the resistance of heating the water,convection to and throught the copper jacket, then the vessel and into material it turns about 10Kw wich is much closer to the real value because there was a heating boiler of about 7Kw that operated for 2 hr to heat the material that was latter taken appart(I dont know the final temp, only that was good enought).
So what am I missing?
Thanks
Best Regards
Roman Katz