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  • Users: takio
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  1. takio

    How can I calculate the axial load F1, F2, when having eccentrical loading.

    Thank you Deserfox. So did you consider F1 location as pivot? Would you please help me with this once again? What would happen if there are two hollowed structure with one shaft? Would that be.. -P*a=F2*2B=F3*(2B+C)=F4*(4B+C)
  2. takio

    How can I calculate the axial load F1, F2, when having eccentrical loading.

    Hello Can anyone please help me with this? The shaft is located through the two holes on the rectangular hollowed structure. When applying the load P, How can I calculate the force 1 and 2? Thank you
  3. takio

    Eccentric load cases.

    Hello rb1957 I have calculated bolt group as below.
  4. takio

    A-Frame, method of joints.

    Hello Thank you for your comment. I have calculated the frame, using the moment and direct load. I hope this makes sense. Thank you
  5. takio

    A-Frame, method of joints.

    Hello rb1957 Thank you so much for your comments ! I am sorry that I didn't specify the other length. I edited it. and, I am s Ideal truss - Pin-connected : no moments. - Internal force in members : only compression or tension, no shear - Assumptions : frictionless joints, nodes are only at...
  6. takio

    A-Frame, method of joints.

    ...CB, and AB. I think I can calculate forces using 1)+2), using truss analysis (method of joints). Am I on right track? For 1) F= W/2 For 2) M=WD,, But I have also M=W/2*L, and theses two has different directions. This gets me confused. Would you give me some ideas on the calculations...
  7. takio

    Eccentric load cases.

    Thank you very much all. I refreshed my strength of materials, and I started getting hang of bolt groups. I used https://mechanicalc.com/reference/bolt-pattern-force-distribution This website and calculated some problems, by following the equations and explanations.
  8. takio

    Eccentric load cases.

    ...of Bolted Joints When Load Is Parallel to the Axis of Bolt - Design of Machine]https://www.youtube.com/watch?v=pnnBTB6RgNk[/url] [1] M=Fr*H - Fa*L : Why do we have to substract Fa*L? I thought theses two components has to be added together...
  9. takio

    Bolt axial force.

    Hello all Thank you so much for helping me out. I think I got hang of the load calculations! I appreciate all the comments !
  10. takio

    Bolt torque-safety factor in member relation

    Hello all I ran FEA to see SF on the carbon steel member. I used Carbon steel yield limit = 46000 PSI The carbon steel surface area that bolt contacts to : 0.3in^2 Applied preload = 10440 lbf (109 lb-in) Stress = 34800 psi SF = 1.3 Thank you for the information on HSLA steel
  11. takio

    Bolt torque-safety factor in member relation

    Hello, Thank you for your comment again. Yes that's what I meant,, it's carbon steel material.
  12. takio

    Bolt torque-safety factor in member relation

    Hello When applying recommended torque from clamp manufacturer. (They said the clamp safety factor is 5, when using 109 ft lbs for 0.375 steel member.) I get safety factor of 1.5~2 in members at bolt joint surface. but my requirement for the member safety factor is 3. In this case, is this...
  13. takio

    Eccentrically loaded bolted joint-Shear force.

    Hello Warose For me, I got 502 lbf. (250 lbs force cantilevered 21.5" to the c.g. of the (4) bolt group) I just calculated with the same method above, but using 250 lbf Thank you
  14. takio

    Eccentrically loaded bolted joint-Shear force.

    Hello I have recalculated as below. I hope this is right. 1) V=500 LBF 2)Total moment at centroid Ma=250 LBF * 1.75 in Mb=250 LBF * (18.5+2.75) in Mt = 250 * (18.5+2.75+1.75) lbf in = 5750 lbf in 3) r = 3.02 in (bolt distance from centroid) 4) Primary shear load per bolt F' = 500 lbf / 4 =...
  15. takio

    Eccentrically loaded bolted joint-Shear force.

    Hello Thank you for your comment again! I just quickly calculated. 1)Moment caused by the load = 250*1 2)Assuming all the bolts are equally spaced in a circle. All the bolts are 3 inches away from the centroid. 3)Load that is tangent to the circle = 250 lbf in / 3 in = 166.67 lbf 4) X and Y...
  16. takio

    Eccentrically loaded bolted joint-Shear force.

    Hello I managed to calculate resultant shear force acting on P1, which is caused by the far end force, 250lbs. (P1 has the highest shear force), thanks to the link below. and it is 505 lbf. but I have trouble finding shear force acting on the bolts, due to the force on the right most side...
  17. takio

    Bolt axial force.

    [b]@Rogue909 Thank you for your comment. I think what you are saying is that the bolt will eventually start feeling load, when the external load exceeds the preload. then, this extra load will affect the bolt safety factor. I actually read that the bolt safety factor should be higher than 3...
  18. takio

    Bolt axial force.

    Hello @ desertfox @ rb1957 I am curious about the direct shear load. I think the moment calculated from desertfox and rb1957 are identical.(rb1957's second approach) but desertfox added direct shear load to the load calculated from moment. and rb1957 didn't add the direct shear load.
  19. takio

    Bolt axial force.

    Hello rb1957 I can understand your 2nd approach very well. I appreciate it. but, I still don't understand 5.5" to calculate load on LH. I still think it should be 2.75" which is the distance between LH and CL. Is this your 1st approach? 1)Calculate Moment around CL. 2)When calculating load on...
  20. takio

    Axial load on bolt

    Hello Could anyone help me with finding out the axial load on the bolts? Thank you

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